n^2+7n+12=10000

Solution for n^2+7n+12=10000 equation:

n^2+7n+12=10000

We move all terms to the left:

n^2+7n+12-(10000)=0

We add all the numbers together, and all the variables

n^2+7n-9988=0

a = 1; b = 7; c = -9988;
Δ = b2-4ac
Δ = 72-4·1·(-9988)
Δ = 40001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{40001}}{2*1}=\frac{-7-\sqrt{40001}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{40001}}{2*1}=\frac{-7+\sqrt{40001}}{2}
$